The energy cost per hour for pumping water can be calculated in imperial units as
The energy costs of pumping water
C = 0.746 Q h c / (3960 μp μm) (1)
Motion from oscillatory motion and can use that to operate a pump. Serve in a wide range of applications such as pumping water from wells. Or by completely removing the pendulum system and first transmitting wheel, we can attach. If the pump doing the lifting is powered by some kind of pendulum engine, it will require 83 lb-ft (26.89 calories) of energy input (and that is with a 100% efficient engine which incidently doesn't exist) to keep the pendulum device swinging and the pump pumping, otherwise the pendulum will stop cold and the pumping will stop cold.
where
![River water pumping systems River water pumping systems](https://www.pendulum-lever.com/images/pendulum-pump2a.jpg)
C = cost per hour (USD/hour, EUR/hour, ...)
Q = volume flow (US gpm)
h = differential head (ft)
c = cost rate per kWh (USD/kWh, EUR/kWh, ....)
μp = pump efficiency (0 - 1)
μm= motor efficiency (0 - 1)
Alternative calculation in metric units
C = q ρ g hc / (3.6 106μp μm)
= q p c / (3.6 106μp μm) (2)
![Lake Lake](https://i.ytimg.com/vi/8n7mvpLpP5A/maxresdefault.jpg)
where
q = volume flow (m3/h)
ρ = density (1000 kg/m3)
h = differential head, height (m)
g = acceleration of gravity (9.81 m/s2)
Example - Pumping Energy Cost
10 US gpm is lifted 10 ft. The electricity cost is 0.1 USD/kWh and the pump and motor efficiency 90% (0.9). The cost per hour can be calculated as
C = 0.746 (10 US gpm) (10 ft) (0.1 USD/kWh) / (3960 0.9 0.9)
= 0.002 USD/hour
Pumping Energy Cost Calculator
- 1 US gpm = 0.227 m3/h
- 1 ft = 0.305 m
Related Topics
- Pumps - Piping systems and pumps - centrifugal pumps, displacement pumps - cavitation, viscosity, head and pressure, power consumption and more
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